find the remainder when p(x)=2x²+7x-4 is divided by x-3
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Given, p(x)=2x 2
−5x+7 and q(x)=x−1
q(x) ⇒x−1=0 ⇒x=1
The remainder when p(x) is divided by q(x) is p(1) (By Remainder Theorem)
Thus,
p(1)=2(1)
2
−5(1)+7
p(1)=2−5+7
p(1)=4
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Answer:
35
by long division method
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