find the remainder when p(x)=32x^5-1 is divided by 4x^2-1
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Answer:
2x -- 1
Step-by-step explanation:
8x^3 + 2x
-----------___________
4x^2--1 ) 32x^5 -- 1
' -- (32x^5 -- 8x^3)
' ----------------------
' 0 + 8x^3 -- 1
' -- (8x^3 --2x)
' ____________
= (0 + 2x -- 1 )
so remainder is 2x -- 1
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