Question

find the remainder when p(x) = 3x ^4 - 2x square - 4x square + x - 6 divided by x - 2

Answer 1

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Answer 2

Given,

p(x) = 3x⁴ - 2x³ - 4x² + x - 6

Using  remainder  theorem , To find  remainder when p(x) is divided  by  x-2 , We can put  x-2=0 or x = 2 in p(x).

Remainder  = 3×2⁴ - 2×2³ - 4×2² + 2  - 6  

                   =  48 - 16 - 16  - 6

                   = 48 - 32 - 6

                   = 48 - 38

                   =  10 .