Find the remainder when p(x)= 3x²+x-1 is divided by 3x-2
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Step-by-step explanation:
By remainder theorem,
find the value of x in 3x-2 and substitute it in 3x²+x-1
3x-2=0
x= 2/3
substitute x= 2/3 in 3x²+x-1
3× (2/3)² +2/3-1
3×4/9+2/3-1
12/9+2/3-1
simplify 12/9 = 4/3
4/3+2/3-1
6/3-1
since 6/3 = 2 ,
2 - 1 = 1
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