Find the remainder when p(x)=3xsquare plus 2x minus 7 is divided by 2x plus 1
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As 2x+1 is deviding
2x+1 = 0 { According to Remainder Theorem}
2x+1 = 0 { According to Remainder Theorem}x = -1/2
Now p(x) = 3x²+2x-7
So, P(-1/2)= 3(-1/2)²+2(-1/2)-7
= 3/4 -1-7
= (3-32)/4 = -29/4
So Remainder is -29/4
Hope it help you
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