find the remainder when p(x)=4x^3-12x^2+14x-3 is divided by g(x)= 2x-1
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Answered by
0
Answer:
2x-1/4X3-12×2+14C-3
Step-by-step explanation:
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Answered by
4
Answer:
Step-by-step explanation:
Given polynomial p(x)=4x³-12x²+14x-3
and g(x)=2x-1
we know that by Remainder theorem
If p(x) is divided by (x-a) then the remainder is p(a)
now given g(x)=2x-1=0
=>2x=1
=>x=1/2
P(x) is divided by 2x-1 then the remainder is p(1/2).
p(1/2)=>4(1/2)³-12(1/2)²+14(1/2)-3
=>p(1/2)=>4(1/8)-12(1/4)+(14/2)-3
=>p(1/2)=4/8-12/4+14/2-3
=>p(1/2)=1/2-3+7-3
=>p(1/2)=1/2+7-6
=>p(1/2)=1/2+1
=>p(1/2)=(1+2)/2
=>p(1/2)=3/2
The remainder =3/2
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