Question

. Find the remainder when p(x) = 9x^3 - 3x^2 + x - 5 is divided by x - 2/3.​

Answer 1

Step-by-step explanation:

X-2/3=0

X=2/3

9X^3-3X^2+X-5

9(2/3)^3-3×(2/3)^2+2/3-5

9×8/27-3×4/9+2/3-5

8/3-4/3+2/3-5

6/3-5

2-5= -3

Answer 2

Answer:

p(x)=3x²+x-5

q(x)=x-2/3

remainder(x)=3x+5/3