Question

find the remainder when p(x) = x^2-2x^3-3x^3-5x+8 is divided by x-2​

Answer 1

Answer:

Step-by-step explanation:

Given, polynomial, p(x)=2x  

3

+5x  

2

−3x−2 divided by (x−1).

The polynomial is divided by (x−1) .

Then put (x−1)=0⟹ x=1  

we get,

p(1)= 2(1)  

3

+5(1)  

2

−3(1)−2

⇒p(1)=2+5−3−2

⇒p(1)=2+5−5

⇒p(1)=2.

So, when p(x)= 2x  

3

+5x  

2

−3x−2 is divided by x−1, the remainder obtained is 2.