Question

find the remainder when P(x)= x^3+1 divided by x-1​

Answer 1

Answer:

p(x) = x³+1

g(x) = x-1

According to remainder theorem -

x-1 = 0

x = 1

p(1) = (1)³+1

= 1+1

= 2

2 is the remainder of p(x)...

Answer 2

Answer:

2

Step-by-step explanation:

if x-1 =0

=> x=1

P(1) = 1³+1= 2

remainder = 2