find the remainder when p(x)=x^3-2x^3-4x-1 is divided by g(x) = [x+1]
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Answer:
given
p(x) = x^3 - 2x^2 - 4x - 1
g(x) = (x + 1)
to find the remainder when p(x) is divided by g(x)
using remainder theorem,
let g(x) = x+1 = 0 therefore x = -1
p(-1) = (-1)^3 - 2(-1)^2 - 4(-1) - 1
=> -1 -2(1) +4 - 1
=> -1 -2 + 4 - 1
=> - 4 + 4
=> 0
hence the remainder is zero
as the remainder is zero, x+ 1 is a factor of p(x)
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