Question

find the remainder when P(x) = x^3 + 3x^2 + 3x + 1 is divided by g(x) = 5 + 12x .

Answer 1

$\small \bold \red{Given \: p(x)=x^3−3x^2+4x+50 \: and \: g(x)=x−3}$

Here, p(x) is divided by g(x)

$\small \bold \red{The \: remainder \: is \: p(3) =3^3−3(3)^2+4×3+50}$

(By Remainder Theorem)

=27−27+12+50

=62

Thus, the remainder is 62