FIND THE REMAINDER WHEN P (x) = x^3 - 3x² + 3x + 2 is divided by x-1÷2
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Answer:
Step-by-step explanation:
x-1/2= 0
x=1/2
put p(x)= 1/2
p(x)=x³-3x²+3x+2
p(x)=(1/2)³-3(1/2)²+3(1/2)+2
p(x)=1/8-3×1/4+3/2+2/1
p(x)=1/8-3/4+3/2+2/1
Lcm of 8,4,2 and1= 8
- 1/8×1/1=1/8
- -3/4×2/2=-6/8
- 3/2×4/4=12/8
- 2/1×8/8=16/8
p(x)=1-6+12+16/8
p(x)=11/8
Therefore, The remainder is 11/8.
Properties Used:-
- Remainder theorem
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