Find the remainder when p(x) = x^3 - 6x^2 + 14x - 3 is divided by g(x) = 1 - 2x and verify the result by long division
Answers
Answered by
2
Answer:
21/8
Step-by-step explanation:
Given : p(x)=x
3
−6x
2
+14x−3,g(x)=1−2x
p(
2
1
)=(
2
1
)
2
−6(
2
1
)
2
+14(
2
1
)−3
=
8
1
−
4
6
+7−3
=
8
1−12+32
=
8
21
Answered by
4
Answer:
Given : p (x) = x^3 − 6x^2 + 14x − 3, g (x) = 1 − 2x
p (1/2 ) = ( 1/2 )^ 2 − 6 (1/2 )^2 + 14 (1/2 ) −3
= 1/8 - 6/4 + 7 - 3
= (1 - 12 + 32)/8
= 21/8
Step-by-step explanation:
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