Question

find the remainder when p(x)=x^3-6x^2+2x-4 is divided by g(x) =1-3/2x​

Answer 1

Answer:

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Step-by-step explanation:

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HERE IS THE ANSWER.....

Given , p(x) = x^3-6x^2+2x-4

g(x) = 1-3/2x

Therefore , zero of g(x) = -1

p(-1) = (-1)^3 - 6(-1)^2 + 2x -4

= -1 - 6+ 2(-1) - 4

= -1 - 6 - 2 - 4

= - 13 is the remainder.....

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