Question

Find the remainder when p(x) = x^3- 6x^2+ 2x-4 is divided by q(x) = 1-2x

Answer 1

Answer:

using factor theorem

Step-by-step explanation:

1-2x=0

-2x=-1

x=1/2

put value in p(x)-:

(1/2)^3-(6*1/2)^2+2x-4

=1/8-36/4+4-2x

=(1-72+32)/8-2x

=-41/8-2x

=-2x-41/8

Ans=-2x-41/8