Find the remainder when p(x)=x?- 6x2 + 14x-3 is divided by g(x) = 1 - 2x and
verify the result by long division.
Answers
Given, g(x) = 1 - 2x = 0 i.e x = 1/2 ----------------- (i)
p(x) = x^3-6x^2+14x-3
- 6x^2 - 1
_________________
1 - 2x ) x^2 - 6x^2 + 2x - 4 (
12x^2 - 6x^2
_____________
- 11x^3 + 2x - 4
+ 2x - 1
_______________
- 11x^3 - 3
We have got remainder as - 11x^3 - 3 (we know that x = 1/2 in (i)
= -11/8 - 3/1
= -11 - 24 /8
= -35/8
Hope this helps!