Question

find the remainder when p(x) = x³-3x²+4x+32 is divided by x+2
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Answer 1

Answer:

g (x)=x+2

x= -2

put the value of x

p (x)=x^3-3x^2+4x+32

p(-2)=(-2)^3-3 (-2)^2+4 (-2)+32

= -8-12-8+32

=-28+32

=4

so remainder is 4

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