find the remainder when p（x）=x³- 5x²- 6x- 2 is di ided by x-1
nitu86bxrpcq5ta:
-12
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Answered by
0
x-1=0
or, x=1
p(1)= 1^3-5×1^2-6×1-2
or, p(1)= 1-5×1-6-2
or, p(1)= 1-5-8
or, p(1)= -4-8
or, p(1)= -12 ans
or, x=1
p(1)= 1^3-5×1^2-6×1-2
or, p(1)= 1-5×1-6-2
or, p(1)= 1-5-8
or, p(1)= -4-8
or, p(1)= -12 ans
Answered by
0
x-1
;:x =1
p(1)= 1^3-5×1^2-6×1-2
= 1-5-6-2
= -12
therefore -12 is the remainder of p (x)
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;:x =1
p(1)= 1^3-5×1^2-6×1-2
= 1-5-6-2
= -12
therefore -12 is the remainder of p (x)
pls make me brainlist I need only one more to get on another level pls
If u mark me the god will bless u and u become topper
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