. Find the remainder when p(x)= x3 – 6x² + 14x – 3 is divided by g(x) = 1 - 2x and
verify the result by long division.
3 12,2
ar this divided hy (x-2) leaves remainder 2, and
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0
Answer:
Given : p(x)=x
3
−6x
2
+14x−3,g(x)=1−2x
p(
2
1
)=(
2
1
)
2
−6(
2
1
)
2
+14(
2
1
)−3
=
8
1
−
4
6
+7−3
=
8
1−12+32
=
8
21
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