Question

find the remainder when p(x)=x³-6x²+14x-3 is divided by g(x)=1-2x and verify the result by long division​

Answer 1

First of all we will find the root of g(x).

g(x) =

$1 - 2x = 0$

that ways x = 1/2.

applying remainder theorem.

The remainder when p(x) is divided by g(x):

p(1/2)

$p( \frac{1}{2} ) = {( \frac{1}{2}) }^{3} - 6 { (\frac{1}{2} )}^{2} + 14 (\frac{1}{2} ) - 3$

p(1/2) = 21/8

Answer 2

Answer:

Answer is 21/8

Step-by-step explanation:

above attached...

hope it is helpful