Find the remainder when p(x) = x³-6x²+2x-4 is divided
by 1 - 2x
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Answer:
let p(x)=1-2x
then,
p(x)=0
1-2x=0
x=1/2
putting the value of x=1/2 in the given equation
p(1/2)={(1/2)^3-6(1/2)^2+2(1/2)-4]
=(1/8-6×1/4+2×1/2-4)
=(1/8-3/2+2/1-4/1)
=(1-12+8-32)/8
=(9-44)/8
=-35/8
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