Question

Find the remainder when p(x)=x³-6x²+2x-4 is divided by g(x)=1-3x.​

Answer 1

Given=

$p(x)=$$x^{3}-6x^{2}+2x-4$

$g(x)=1-3x\\1-3x=0\\1=3x\\x=1/3$

$p(1/3)=(1/3)^3-6(1/3)^2+2*(1/3)-4\\ =1/27-2/3+2/3-4\\=\frac{1}{27} -4\\=\frac{1-108}{27} \\=\frac{-107}{27}\\This\\is\\the\\remainder$

Answer 2

Answer:

hi dear❣️❣️

ans is -35/8

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