Question

Find the remainder when P(y) = y2 – 3y -5 is divided by 2y-1.​

Answer 1

Answer:

y=1/2 . now we can solve by remainder theorem

1/2*2-1/2*3-5

1-3/2-5

2-3-10/2

-11/2

hope this may help you

Answer 2

Question :-

Find the remainder when P(y) = y2 – 3y -5 is divided by 2y-1.

Answer :-

》》2y - 1 = 0

2y = 1

y = 1/2

• Substitute the value of y in the equation given

${y}^{2} - 3y - 5 \\( { \frac{1}{2} })^{2} - 3( \frac{1}{2} ) - 5 \\ \frac{1}{4} - \frac{3}{2} - 5 \\ \frac{1 - 6 - 20}{4} \\ \frac{ - 25}{4}$