Find the remainder when polynomial x³+3x²+3x+1 is divided by x+1
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Answered by
2
Answer:
remainder=0
Step-by-step explanation:
x+1)x³+3x²+3x+1(x²+2x+1
-x³-1x
__________
2x²+3x+1
-2x²-2x
___________
1x+1
1x+1
_____________
0
hence it is completely divisible by x+1
so, remainder will be 0 and q=x²+2x+1
hope it helps you......
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Answered by
0
By remainder theorem
x+1=0
x=-1
p(x ) = x³ + 3x² - 3x - 1
p( -1 )=( -1 )³+ 3( -1 )²-3 ( -1 ) -1
= -1 + 3 ( 1 ) +3-1
= -1 + 3 + 3-1
= 6 - 2
=4
Thus remainder is 4
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