Find the remainder when r° + 3r? + 3x + 1 is divided by 1 (ii) x (ii) x- (1) xt1 2.
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Answer:
(i) If x+1=0, then x=−1
So put the value of x=−1 in equation x3+3x2+3x+1 we get
(−1)3+3(−1)2+3(−1)+1=−1+3−3+1=0
Remainder is 0.
(ii) If x−21=0, then x=21
So, put x=21 in equation, we get
(21)3+3(21)2+3(21)+1=81+43+23+1=820=25
(iii) If x+0=0 then x=0
So put the value of x=0 in equation x3+3x2+3x+1 we get
(0)3+3(0)2+3(0)+1=0+0+0+1=1
Remainder is 1.
HOPE IT HELPS YOU ☺️
Answered by
1
Answer:
(i) If x+1=0, then x=−1
So put the value of x=−1 in equation x3+3x2+3x+1 we get
(−1)3+3(−1)2+3(−1)+1=−1+3−3+1=0
Remainder is 0.
(ii) If x−21=0, then x=21
So, put x=21 in equation, we get
(21)3+3(21)2+3(21)+1=81+43+23+1=820=25
(iii) If x+0=0 then x=0
So put the value of x=0 in equation x3+3x2+3x+1 we get
(0)3+3(0)2+3(0)+1=0+0+0+1=1
Remainder is 1.
HOPE IT HELPS YOU ☺️
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