Question

Find the remainder when r° + 3r? + 3x + 1 is divided by 1 (ii) x (ii) x- (1) xt1 2. ​

Answer 1

Answer:

(i) If x+1=0, then x=−1

So put the value of x=−1 in  equation x3+3x2+3x+1 we get

(−1)3+3(−1)2+3(−1)+1=−1+3−3+1=0 

Remainder is 0.

(ii) If x−21=0, then x=21

So, put x=21 in equation, we get

(21)3+3(21)2+3(21)+1=81+43+23+1=820=25

(iii) If x+0=0 then  x=0

So put the value of x=0 in  equation x3+3x2+3x+1 we get

(0)3+3(0)2+3(0)+1=0+0+0+1=1

Remainder is 1.

HOPE IT HELPS YOU ☺️

Answer 2

Answer:

(i) If x+1=0, then x=−1

So put the value of x=−1 in  equation x3+3x2+3x+1 we get

(−1)3+3(−1)2+3(−1)+1=−1+3−3+1=0 

Remainder is 0.

(ii) If x−21=0, then x=21

So, put x=21 in equation, we get

(21)3+3(21)2+3(21)+1=81+43+23+1=820=25

(iii) If x+0=0 then  x=0

So put the value of x=0 in  equation x3+3x2+3x+1 we get

(0)3+3(0)2+3(0)+1=0+0+0+1=1

Remainder is 1.

HOPE IT HELPS YOU ☺️