Question

Find the remainder when summation r=0to 2014 summation k=0tor (-1)^k(k+1)(k+2)2019Cr-k

Answer 1

Answer:

3x+2y = 18Given equations are

2x+3y=11−−−−(1)

2x−4y=−24−−−−(2)

Form (1)

2x+3y=11

⇒2x=11−3y

⇒x=

2

11−3y

−−−(3)

substituting x in(2)

2x−4y=−24

⇒2(

2

11−3y

)−4y=−24

⇒11−3y−4y=−24

⇒11−7y=−24

⇒7y=35

⇒y=35/7

⇒y=5.

putting y = 5 in (3)

x=

2

11−3(5)

⇒x=

2

11−15

⇒x=−4/2

∴x=−2.

Hence x = -2 and y = 5 is the solution of the

equation.

Now, we have to find m

y=mx+3 ∴m=−1

5=3(−2)+3

5−3=−2m⇒−2m=2

⇒m=−2/x=−1