Question

Find the remainder when t3 +3kt2 -k2 t+2k3 is divided by t-2k​

Answer 1

Answer:

Remainder = 20k³

Step-by-step explanation:

let the polynomial f(x) = t³ + 3kt² - k²t + 2k³

f (2k) = t³ + 3kt² - k²t + 2k³

f (2k) = (2k)³ + 3k.(2k)² - k².2k  + 2k³

f (2k) = 8k³ + 3k.4k² - k².2k + 2k³

f (2k) =  8k³ + 2k³ + 12k³ - 2k³

f (2k) =  10k³ + 10k³

f (2k) =  20k³

( I have doubt, not completely sure of the answer. Let me know, if its wrong.) The method for Factorization is correct, but Not sure in case of answer)