find the remainder when
is divided by:-
(1) X+1
(2)x
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Answered by
0
For finding the remainder, we need to use remainder theorem.
let p(x)=x
3
−2x
2
+x+1
Hence, to find the remainder on dividing by x−1, we need to equate it to 0 and put that value of x in p(x).
⇒x−1=0
⇒x=1
p(1)=1
3
−2×1
2
+1+1
p(1)=1
Answered by
8
1) x³+2x²+2x+1÷x+1
By remainder theorem:
Let the root of p(x) = x³+2x²+2x+1 be x+1=0 i.e x= -1
Therefore,
p(-1) = (-1)³+2(-1)²+2(-1)+1
= -1+2-2+1
= 0
Therefore, remainder= 0
2) x³+2x²+2x+1 ÷ x
By remainder theorem:
Let the root of p(x) = x³+2x²+2x+1 be x=0
Therefore,
p(0) = (0)³+2(0)²+2(0)+1
= 1
Therefore, remainder= 1
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