find the remainder when
![x^{3} + 3x^{2} + 3x + 1 x^{3} + 3x^{2} + 3x + 1](https://tex.z-dn.net/?f=x%5E%7B3%7D+%2B+3x%5E%7B2%7D+++%2B+3x+%2B+1)
divided by
![x + \pi x + \pi](https://tex.z-dn.net/?f=x+%2B+%5Cpi)
Answers
Answered by
109
Heya!!
Thanks for asking the question .
The solution to your question is in the above picture.
Hope it helps you.
Thanks for asking the question .
The solution to your question is in the above picture.
Hope it helps you.
Attachments:
![](https://hi-static.z-dn.net/files/df6/f9bf327a742ca62b995d29a8964f2b8e.jpg)
![](https://hi-static.z-dn.net/files/dc2/79bc41fab5dfe294650ecab21f357d39.jpg)
Prakhar2908:
Oh sorry again.
Answered by
84
{ The answer is provided in the given attachment }
The remainder is
= 1 - 3π + 3π² - π³
= - 3375/343
#MarkAsBrainliest
Attachments:
![](https://hi-static.z-dn.net/files/d33/d413c196222673680b5b97d2b947471e.jpg)
Similar questions