Question

find the remainder when
$x^{3} - ax^{2} + 6x - a$
is divided by
$(x - a)$
is anyone here to help me to find the solution of this question

Answer 1

According to remainder theorem,

If a polynomial p(x) divided by (x-a) then remainder equal to p(a).

According to ur question,

p(x) = x​3​​−ax​2​​+6x−a 

Remainder also equal to p(a)

=) p(a) = a^3 - a(a) ^2 + 6(a) - a

= a^3 - a^3 + 6a - a

= 5a

Hope it's helpful to u.