Question

find the remainder when
${x}^{3} + {ax}^{2} + 6x - a$
is divided by
$x - a$

Answer 1

hiii!!!

here's ur answer...

given :-

p ( x ) = x³ + ax + 6x - a

g ( x ) = x - a

therefore x = a

on putting values :-

= (a)³ + a (a)² + 6 (a) - a

= a³ + a³ + 6a - a

= 2a³ + 5a

hope this helps..!!

Answer 2

here x-a
x-a =0
x=a

we can replace x by a

x^3+ax^2+6x-a

a^3+a(a)^2+6a -a

a^3+a(a×a)+6a-a

a^3+a^3 +5a

a ^6 +5a

this is your answer....

hope it helps to you