Question

find the remainder when the number 9^100 is divided by 8​

Answer 1

Answer:

We'll do this using binomial theorem.

9 = 8+1

so we need to find the remainder when (1+8)^100 is divided by 8

expansion => 100 c 0 + 100 c 1 * 8 + 100 c 2 * 8^2+ ...........+ 100 c 100 * 8^100

when we divide this by 8, every term would be divisible except the first term.

so remainder will be 1 ( since 100 c 0 = 1)

[ 1/8 remainder = 1 ]

Answer 2

Answer:

This is your answer

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