Find the remainder when the polynomial P(x)=x^4+2x^3-3x^2+x-1 is divided by (x-2)
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Question:-
Find the remainder when the polynomial P(x)=x⁴+2x³-3x²+x-1 is divided by (x-2)
Given:-
p(x) = x⁴+2x³-3x²+x-1
g(x) = x-2
To Find:-
Remainder =?
Explanation:-
p(x) = x⁴+2x³-3x²+x-1
g(x) = x-2
= x-2=0
= x=2
Putting x=2 in p(x)
p(x) = x⁴+2x³-3x²+x-1
= (2)⁴+2×(2)³-3×(2)²+2-1
= 16 + 2× 8-3×4+2-1
= 16+16-12+2-1
= 32-12+2-1
= 34-12-1
= 34-13
= 21
Hope it helps!
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