find the remainder when the polynomial p( x) =x ^61 + 61 is divided by x-1
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Answered by
9
Hiii!!
Here's Ur answer...
We can find it's remainder by two methods, but we will use the easier one "remainder theorem"
p(x) = x^61 + 61
G(x) = x - 1
→ x - 1 = 0
→ x = 1
So value of x is 1
Therefore p(1) = 1^61 + 61
= 1 + 61
= 62
Hence, remainder is 62
Hope this helps..!!
Here's Ur answer...
We can find it's remainder by two methods, but we will use the easier one "remainder theorem"
p(x) = x^61 + 61
G(x) = x - 1
→ x - 1 = 0
→ x = 1
So value of x is 1
Therefore p(1) = 1^61 + 61
= 1 + 61
= 62
Hence, remainder is 62
Hope this helps..!!
Answered by
2
Answer:
.......62
......... hope you clear
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