find the remainder when the polynomial p(x)=x4+2x3-3x2+x-1 is divided by g(x)=x-2
class 9 CBSE
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Answer:
Remainder = 21
Step-by-step explanation:
Given:
- p(x) = x⁴ + 2x³ - 3x² + x - 1
- g(x) = x - 2
To find:
Remainder = ?
Solution:
In this question, p(x) is divided by g(x). So, equate g(x) to 0. You will obtain the value of x. Substitute this value of x in p(x) equation and you will get the remainder. This procedure is known as the 'Remainder theorem'
g(x) = x - 2 = 0
⇒ x - 2 = 0
⇒ x = 2
Put this value of x in p(x) Equation.
p(x) = x⁴ + 2x³ - 3x² + x - 1
p(2) = (2)⁴ + 2(2)³ - 3(2)² + 2 - 1
⇒ p(2) = 16 + 16 - 3(4) + 2 - 1
⇒ p(2) = 32 - 12 + 2 - 1
⇒ p(2) = 21
∴ The remainder when p(x) is divided by g(x) = 21
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