Question

Find the remainder when the polynomial P(y) = y^4 -2y^2 +3y -1 is divided by g(y)=y - 1​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$g(y) = y - 1 \\ 0 = y - 1 \\ 1 = y \\ p(y) = {y}^{4} - {2y}^{2} + 3y - 1 \\ applying \: y = 1 \\ p(1) = {1}^{4} - {(2)(1)}^{2} + 3(1) - 1 \\ = 1 - 2 + 3 - 1 \\ = 1$

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