find the remainder when the polynomial p(y) =y⁴-3y²+7y-10 is divided by y-2
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1) p ( y ) = y⁴ - 3y² + 7y - 10 ÷ y - 2
soln: By remainder theorem:
Let the root of of p(y) = y⁴ - 3y² + 7y - 10 be y - 2 = 0 i.e y = 2
therefore,
p ( 2 ) = ( 2 )⁴ - 3 ( 2 )² + 7 ( 2 ) - 10
= 16 - 12 + 14 - 10
= 30 - 22
= 8
therefore, remainder = 8
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