Find the remainder when the polynomial x^3+x^2+x+1 is divided by x-1 upon 2
Answers
Answered by
1
Answer:
27/8
Step-by-step explanation:
Given, p(x)=x
3
+3x
2
+3x+1.
We find remainder using, x−
2
1
=0⟹x=
2
1
.
Then,
P(
2
1
)=(
2
1
)
3
+3(
2
1
)
2
+3(
2
1
)+1
=
8
1
+
4
3
+
2
3
+1
=
8
1+6+12+8
=
8
27
.
Therefore, the required remainder =
8
27
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