find the remainder when the polynomial (y³-4y²+1)is divided by (y-3)
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Answered by
25
Answer:
2y+3 )4y3−3y2−5y+1( 2y2−29y+417
4y3+6y2
(−)
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−9y2−5y
−9y2−227y
(−)
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217y+1
217y+451
(−)
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−447
2y+34y3−3y2−5y+1=2y2−29y+417−4(2y+3)47
Answered by
2
Answer:
-8 is the remainder .
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