find the remainder when when 4x³-7x²+3x-1 is divided by 2x-1
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Answer:
X=-1/2
Step-by-step explanation: 4(1/2)*3-7(-1/2)+3x-1
=4(1/8)-7(-1/4)+3(-1/2)-1
=-1/2+7/4+-3/2-1
=-1-3/2+7/4-1
=-2/2+7/4-1
LcM=-8+7/4-1
=-1/4-1
=-2/4
=-1/2
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