Math, asked by aasimnewyork, 7 months ago

find the remainder when when 4x³-7x²+3x-1 is divided by 2x-1​

Answers

Answered by rithikeshsathish875
2

Answer:

X=-1/2

Step-by-step explanation: 4(1/2)*3-7(-1/2)+3x-1

=4(1/8)-7(-1/4)+3(-1/2)-1

=-1/2+7/4+-3/2-1

=-1-3/2+7/4-1

=-2/2+7/4-1

LcM=-8+7/4-1

=-1/4-1

=-2/4

=-1/2

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