Question

find the remainder when when p​

Answer 1

Answer:

p(x)=x3−6x2+2x−4 and

g(x)=1−23x

   1−23x=0

=>23x=1

=>x=32

By, remainder theorem, the remainder when p(x) divided by g(x) is p(32)

Thus, 

p(32)=(32)3−6(32)2+2(32)−4

          =278−96×4+34−4

          =278−98+34−4

          =

Answer 2

Answer:

write hole question...........

Step-by-step explanation:

Then I give you answer