find the remainder when x^100-1 is divided by x-1. (2 question ) find the value of 'k' if (2,3) is a solution of 5x+2y=4k
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The remainder is (-1)^100+100=100+1=101
Given, equation is 5x + 2ky = 3k.
On putting x =1 and y =1 in this equation, we get
5(1) + 2k(1) =3k ⇒ 5 + 2k =3k
⇒ 5 = 3k - 2k ⇒ k = 5
Hence, required value of k is 5.
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Given, equation is 5x + 2ky = 3k.
On putting x =1 and y =1 in this equation, we get
5(1) + 2k(1) =3k ⇒ 5 + 2k =3k
⇒ 5 = 3k - 2k ⇒ k = 5
Hence, required value of k is 5.
Hope It helps you
Plz Mark me as brainliest
maddy0507:
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Hi there here's your answer
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