Find the remainder when x^100 is divided by (x-1)(x-2)
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(x-2)(x-1) = x^2 - 3x +2 . So, x^2 = 2- 3x
Using the remainder theorem,
If we put x ^2 = 2 -3x in x^100, we get tje remainder.
So, x^100 = (x^2) × ( x^98)
= (2-3x) × x^98
= 2x^98 -3x^99
So the ans. is 2 (x^98) - 3 (x^99)
Using the remainder theorem,
If we put x ^2 = 2 -3x in x^100, we get tje remainder.
So, x^100 = (x^2) × ( x^98)
= (2-3x) × x^98
= 2x^98 -3x^99
So the ans. is 2 (x^98) - 3 (x^99)
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