Question

Find the remainder when x^3+3x^2+3x+1 is divided by (i) x-1/2 (ii)x (iii)5+2x​

Answer 1

Answer:

(ii) x –1/2      

Apply remainder theorem

=>x – 1/2 =0

=> x =  1/2

Replace x by  1/2 we get

=>x3+3x2 + 3x + 1

=>(1/2)3 + 3(1/2)2 + 3(1/2) + 1

=> 1/8 + 3/4 + 3/2 + 1

Add the fraction taking LCM of denominator we get

=>(1 + 6 + 12 + 8)/8

=>27/8

Remainder is 27/8

(v) 5 + 2x

Apply remainder theorem

=>5+2x =0

=> 2x = - 5

=> x = - 5/2

Replace x by – 5/2 we get

=>x3+3x2 + 3x + 1

=>(-5/2)3 + 3(-5/2)2 + 3(-5/2) + 1

=> -125/8  + 75/4 – 15/2 + 1

Add the fraction taking LCM of denominator

=>(-125 + 150  - 60 + 8 )/125

=> -27/8

Remainder is -27/8

Answer 2

Answer:

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