find the remainder when x^3 + 3x^2+ 3x + 1 is divided by
Q 1) x-1/2
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Answered by
0
x+1=0
x=−1
p(x)=x
3
+3x
2
−3x−1p(−1)
=(−1)
3
+3(−1)
2
−3(−1)−1
=−1+3(1)+3−1
=−1+3+3−1
=6−2
=4
Thus remainder is 4
Answered by
0
Answer:
1/8+6/8+12/8+8/8=27/8
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