Question

Find the remainder when x^3+3x^2+3x+1 is divided by the following linear polynomials:
5+2x​

Answer 1

Answer:

g(x)=0

5+2x=0

2x=-5

x=-5/2

p(x)=x³+3x²+3x+1

p(-5/2)=(-5/2)³+3(-5/2)²+3(-5/2)+1

=-125/8+3(25/2)-15/2+1

=-125/8+75/2-15/2+1/1

=-125+300-60+8/8

=-185+308/8

=123/8

Hope it will help you!!

Answer 2

Solution :

here..

f(x) is 2x+5

:. x=-5/2

putting value of x in the given polynomial

we get

=(-5/2)^3+3*(-5/2)^2+3*(-5/2)+1

= -125/8+75/4-15/2+1

LCM of 8,4,2 is 8

= -125+150-60+8/8

= 158-185/8

= -27/8

:. Answer is -27/8