find the remainder when x^3+3x^2+3x+1 is divided by x-1/2
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x - 1/2 = 0
⇒ x = 1/2
x³ + 3x² + 3x + 1
(1/2)³ + 3(1/2)² + 3(1/2) + 1
1/8 + 3/4 + 3/2 + 1
(1+6+12)/8 = 19/8 is the remainder
⇒ x = 1/2
x³ + 3x² + 3x + 1
(1/2)³ + 3(1/2)² + 3(1/2) + 1
1/8 + 3/4 + 3/2 + 1
(1+6+12)/8 = 19/8 is the remainder
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