Question

find the remainder when x^3+3x^2+3x+1 is divided by x-1/2

Answer 1

Answer:

Let p(x) = x^3 + 3x^2

Step-by-step explanation:

Let p(x) = x^3 + 3x^2 +3x+ 1

we have zero of x-1/2 = 1/2

remainder =p(1/2)

                = (1/2)^3 +3 (1/2)^2 + 3(1\2) + 1

                = 1/8 + 3/4 + 3/2 + 1

take LCM of 8,4,2,1 = 8

               = 1+6+12+8 by 8

               = 24

hence remainder of p(x) = 24