Question

find the remainder when x^3+3x^2+3x+1 is divided by x+1​

Answer 1

Explanation:

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Answer 2

Answer:

$\huge\underline \mathbb\red{❥︎Answer}$

$→ By \: \: remainder \: \: theorem \: \\ x+1=0 \\ x=-1 \\ =P(x)= {x}^{3} +3 {x}^{2} +3x+1 \\ P(-1)= ({-1})^{3}+ 3({-1})^{2}+3(-1)+1 \\ P(-1)=-1+3-3+1 \\ P(-1)=4-4 \\ P(-1)=0$