Find the remainder when x^3 - 3x^2 - 3x -1 is divided by x-1 solve by using long division method
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Step-by-step explanation:
Given:-
x^3 - 3x^2 - 3x -1
To find:-
Find the remainder when x^3 - 3x^2 - 3x -1 is divided by x-1 solve by using long division method
Solution:-
See the above attachment
On dividing x^3 - 3x^2 - 3x -1 by x-1 then we get
Quotient = x^2-2x-5
Remainder = -6
Answer:-
Quotient = x^2-2x-5
Remainder = -6
Check:-
We know that
Division Rule:-
Dividend = Divisor×Quotient+Remainder
=> (x-1)(x^2-2x-5)+(-6)
=>x(x^2-2x-5)-1(x^2-2x-5)-6
=>x^3-2x^2-5x-x^2+2x+5-6
=>x^3-3x^2-3x-1
=>Given Polynomial
Verified the given relation.
Used formula:-
Dividend = Divisor×Quotient+Remainder
Attachments:
Answered by
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the remainder is x^2-2x-1
Attachments:
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